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November 21, 2014

November 21, 2014

Posted by **Carla** on Thursday, March 29, 2007 at 11:55pm.

your drawing should look like this

......................

. . . .

. . . .

. . . .

. . . .

. . . .

......................

then let the width of the smaller rectangle be x, let its length be y

so the amount of fencing would be

8x + 5y

so 8x+5y=810

y=(810-8x)/5

Area = 4xy = 4x(810-8x)/5

= 648x - 32x^2 /5

d(Area)/dx = 648 - (64/5)x = 0 for a max of Area

solve to get x=50.625

and subst to get y=81

for a max area of 4(50.625)(81)=16402.5

sorry, my diagram did not come out the way I hoped it would.

It is a large rectangle cut into four smaller ones.

Thank you!!!!!!!!!!

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