Friday

October 24, 2014

October 24, 2014

Posted by **Carla** on Thursday, March 29, 2007 at 11:55pm.

your drawing should look like this

......................

. . . .

. . . .

. . . .

. . . .

. . . .

......................

then let the width of the smaller rectangle be x, let its length be y

so the amount of fencing would be

8x + 5y

so 8x+5y=810

y=(810-8x)/5

Area = 4xy = 4x(810-8x)/5

= 648x - 32x^2 /5

d(Area)/dx = 648 - (64/5)x = 0 for a max of Area

solve to get x=50.625

and subst to get y=81

for a max area of 4(50.625)(81)=16402.5

sorry, my diagram did not come out the way I hoped it would.

It is a large rectangle cut into four smaller ones.

Thank you!!!!!!!!!!

**Answer this Question**

**Related Questions**

Calculus - A ostrich farmer wants to enclose a rectangular area and then divide ...

Calc 1 - A farmer with 700 ft of fencing wants to enclose a rectangular area and...

Calculus - A pig farmer wants to enclose a rectangular area and then divide it ...

Maths - A rancher wants to enclose a rectangular area and then divide it into ...

Calculus - A cattle rancher wants to enclose a rectangular area and then divide ...

math - a farmer with 10,000 meters of fencing wants to enclose a rectangular ...

Precalculus - You have a total of 820 feet of fencing to enclose a large ...

calculus optimization problem - A farmer has 460 feet of fencing with which to ...

Algebra 2 - A farmer has 120 ft. of fencing available to enclose 2 adjacent ...

Math - a farmer wants to put a fence around a rectangular field and then divide ...