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November 29, 2014

November 29, 2014

Posted by **Justin** on Thursday, March 29, 2007 at 1:42pm.

The equation is d=sqrt(x^2+(4-x^2-2)^2)

The book tells me that the answer simplifies to sqrt(x^4-3x^2+4).

Can you please help me understand where the -3x^2 came from?

Thanks!

d=√(x^2 + (4 - x^2 - 2)^2)

=√(x^2 + (2 - x^2)^2)

=√(x^2 + x^4 - 4x^2 + 4)

=√(x^4 - 3x^2 + 4)

In my opinion, this is not much of a "simplification" problem

(4-x^2-2)^2 = (2 - x^2)^2 = x^4 - 4x^2 + 4

When you add the x^2 to that, you get

x^4 - 3x^2 + 4

(4 - x^2 - 2)^2 simplifies to (2 - x^2)^2. Expanding it gives x^4 - 2x^2 - 2x^2 + 4 = x^4 - 4x^4 + 4. Then you have that x^2 out in front that you can work with. so x^4 + x^2 - 4x^2 + 4 = x^4 - 3x^2 + 4.

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