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September 30, 2014

September 30, 2014

Posted by **Kate** on Thursday, March 29, 2007 at 12:07am.

y=2x-6x+9

...the 2x is squared.

y = 2x^2 -6x + 9

The vertex is where the function is a minimum. That would be where dy/dx = 4x -6 = 0

x= 3/2

If you are not familiar with calculus, then rewrite the expression

y = 2 (x^2 -3x + (3/2)^2) +9 -(3/2)^2

= 2(x - 3/2)^2 + constant

That has a minimum when x -3/2 = 0

- Pre- Algebra -
**Ashley**, Thursday, August 28, 2008 at 6:27pmmultiply 2 by 2

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