Posted by **mario** on Wednesday, March 28, 2007 at 10:59pm.

drama club sold adult tickets for $8 and kid tickets for $5. for the final performance a total of 226 tickets were sold for a total of $1670. how many adult tickets were sold for the performance?

X = # of adult tickets

Y = # of kid tickets

X + Y = 226

8X + 5Y = 1670

Solve those two equations in two unknowns. One way would be to use substitution. (Insert 226 - X in place of Y in the second equation).

- math -
**John**, Thursday, April 5, 2012 at 6:59pm
Let x = adult's tickets

y = children's tickets

Equation Insert x value in

1. x + y = 226 first equation

180 + y=226

2. 8x + 5y = 1670 y=226-180

By substitution, y=46

x=180,y=46 Ans.

y = 226-226-x

2. 8x + 5(226-x)=1670 multiply

8x + 1130 - 5x=1670 cancellation

8x-5x=1670-1130

3x=540

x=180 continue above:

- math -
**John**, Thursday, April 5, 2012 at 7:02pm
Let x = adult's tickets

y = children's tickets

Equation Insert x value in

1. x + y = 226 first equation

180 + y=226

2. 8x + 5y = 1670 y=226-180

By substitution, y=46

x=180,y=46 Ans.

y = 226-226-x

2. 8x + 5(226-x)=1670 multiply

8x + 1130 - 5x=1670 cancellation

8x-5x=1670-1130

3x=540 divide

x=180 continue above:

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