Tuesday

September 16, 2014

September 16, 2014

Posted by **Jim** on Wednesday, March 28, 2007 at 6:52pm.

(b) Calculate the kinetic energy that the earth has because of its motion around the sun.

Please check. The answer i came up with for a. is wrong.

a.

rotational KE = 1/2(Iw^2)

=1/2(2/5mr^2)w^2

=1/2((2/5(5.98x10^24kg)(6.38x10^6m))(2PI rad/ s)^2

=(7.63048x10^30kg*m)(39.4384/2.49x10^-13)

= 1.210 x 10^18

ur answer is right. I do belive

I don't understand where you got the w^2 The earth's rotational w is

(2 pi rad)/(24*3600 sec) = 7.27*10^-5 rad/s

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