This is a "trial and error" type question. Algebra alone won't help you.
First see what you could do buying 19 cow brains ($95) with $5 left. That could get you ten sheep brains ($1) and two pig brains ($4). The total would be only 31 total. Not enough. So try getting fewer cow brains. With 18 cow brains ($90) you can get 80 sheep brains ($8) and 1 pig brain ($2). Not quite 100 total. The number of sheep brains will have to be divisible by ten to come out with an even number of dollars.
With those rules in mind, see what other combinations might work
On math sheet says.
I have to spend 100.00 and have a hundred brains. There are sheep brains wich are .10cents and then pig 2.00 and then cow 5.00. I have to at least by one of each brain.
I need major help
To solve this trial and error problem, we need to find a combination of sheep, pig, and cow brains that adds up to $100 and gives a total of 100 brains.
Let's start by analyzing the given information. We know that we need to buy at least one of each type of brain (sheep, pig, and cow). The cost of a sheep brain is $0.10, pig brain is $2.00, and cow brain is $5.00.
We'll use a trial and error method to find a solution. Let's keep track of our progress and analyze some combinations:
1. Start with the given combination: 10 sheep brains + 2 pig brains + 19 cow brains.
- Cost: $1.00 + $4.00 + $95.00 = $100.00
- Total brains: 10 + 2 + 19 = 31 brains
By checking this combination, we can see that we don't have enough total brains. We need to find another combination.
2. Reduce the number of cow brains to 18: 80 sheep brains + 1 pig brain + 18 cow brains.
- Cost: $8.00 + $2.00 + $90.00 = $100.00
- Total brains: 80 + 1 + 18 = 99 brains
This combination doesn't give us the desired total of 100 brains. We need to adjust the number of sheep brains so that it is divisible by 10 to have an even number of dollars.
3. Reduce the number of cow brains to 17: 70 sheep brains + 3 pig brains + 17 cow brains.
- Cost: $7.00 + $6.00 + $85.00 = $98.00
- Total brains: 70 + 3 + 17 = 90 brains
Again, this combination doesn't give us the desired total of 100 brains. Let's continue trying different combinations.
4. Reduce the number of cow brains to 16: 60 sheep brains + 5 pig brains + 16 cow brains.
- Cost: $6.00 + $10.00 + $80.00 = $96.00
- Total brains: 60 + 5 + 16 = 81 brains
5. Reduce the number of cow brains to 15: 50 sheep brains + 7 pig brains + 15 cow brains.
- Cost: $5.00 + $14.00 + $75.00 = $94.00
- Total brains: 50 + 7 + 15 = 72 brains
From our previous attempts, we can see that decreasing the number of cow brains is not giving us enough brains. So, let's try increasing the number of cow brains.
6. Increase the number of cow brains to 20: 90 sheep brains + 0 pig brains + 20 cow brains.
- Cost: $9.00 + $0.00 + $100.00 = $109.00
- Total brains: 90 + 0 + 20 = 110 brains
By increasing the number of cow brains, we exceeded the budget of $100.00.
From our attempts, we can conclude that there is no combination of sheep, pig, and cow brains that satisfies the given conditions of spending $100.00 and having a total of 100 brains.
Therefore, the answer to the problem is that there is no solution that meets the requirements.