Posted by **Cavin** on Wednesday, March 28, 2007 at 1:10pm.

A bowling ball encounters a 0.76m vertical rise on the way back to the ball rack. Ignore frictional losses and assume that the mass of the ball is distributed uniformly. If the translational speed of the ball is 3.80m/s at the bottom of the rise, find the translational speed at the top.

I will be happy to critique your thinking or work on this. Remember the ball has translational energy and rotational energy.

sum force= 0

therefore T-F+TRAY+PLATE+CUP

T=1/.04(.240kg(.1m)+(.14m)(1.00kg)+(.28m)(.300kg)=6.2N

Please check my working

## Answer This Question

## Related Questions

- Physics - A bowling ball encounters a 0.76m vertical rise on the way back to ...
- Physics - A bowling ball encounters a 0.760-m vertical rise on the way back to ...
- Physics - A bowling ball encounters a 0.760 m vertical rise on the way back to ...
- physics - A bowling ball encounters a 0.760-m vertical rise on the way back to ...
- Physics - A bowling ball encounters a 0.76 m vertical rise on the way back to ...
- Physics - Equate the increase in potential energy at the higher elevation, M g H...
- Physics please check - A bowling ball encounters a 0.76 m vertical rise on the ...
- Physics - After you pick up a spare, your bowling ball rolls without slipping ...
- physics - After you pick up a spare, your bowling ball rolls without slipping ...
- Physics - After you pick up a spare, your bowling ball rolls without slipping ...

More Related Questions