# please check (physics)

posted by
**susane** on
.

Current flows out of a 110V source through a 10 ohm resistor and then through parallel branches, one containing a 20 ohm resistor and the other a 30 ohm resistor. Find V I R P

V I R P

50 5 10 250

60 3 20 180

60 2 30 120

_____________________________

110 5 22 550

First R total:

1/R= 1/20 + 1/30

1/R= 1/12

12 + 10= 22 ohms

Now I find current:

I= 110/22

I= 5 A

current same in series so 10 ohm resistor is also 5 A

Voltage:

Now I can find 10 ohm voltage

5 * 10= 50 v

110 -50= 60 v left over for parallel

60 v must be in each parallel because treated as one

now I find I of 20 and 30 ohm resistors:

I=60/20

I=60/30

so 3, and 2 ohm

power is P= IV

Please let me know if my thinking is off.

Thank you

it is correct.