Posted by **jasmine20** on Wednesday, March 28, 2007 at 2:26am.

Can someone show me how to solve these types of problems. i have two that are driving me nuts.as of now.

Problem #1

Simplify:

2radical(12) + 4 radical (27)

Problem #2

evaluate if possible the following

i am going to describe it

in the index it has a 3 then a radical and for the radicand it has negative 27

can't help sorry

I hope I have understood the question.

2radical(l2)=2radical(2x2x3)

2radical(2x2x3)=2radical(2x2)x2radical(3)=2x(2radical(3))

4radical(27)= 2radical(3x2radical(3))

=2radical(3)x4radical(3)

adding the two

2x(2radical(3))+2radical(3)x4radical(3)=

taking 2radical(3) out as a factor

=2radical(3)x(2+4radical(3))

Does this help?

for 3radical(-27)

3radical(27) would be 3 [3x3x3=27)

3radical(-27) would be -3 (-3x-3x-3=-27)