# Physics

posted by
**Paula** on
.

If you wish to warm 120 kg of water by 16°C for your bath, how much heat is required?

((The heat capacity of liquid water is 4186 J/(kg·oC) )

Q = M C *(delta T)

delta T = 16 C (it means "change in temperature)

M = 120 kg

C = 4186 J/(kg·oC

Multiply it out for the answer (Q, the heat required), in Joules