Posted by **Karla** on Tuesday, March 27, 2007 at 1:52pm.

Forces F1=7.50N and F2=5.30N are applied tangentially to a wheel with radius 0.330 m. What is the net torque on the wheel due to these two forces for an axis perpendicular to the wheel and passing through its center?

It depends upon whether or not the forces F1 and F2 are both in the same rotational direction. It they are, add the torques. If not, subtract one from the other. For a tangential force, torque = (force)x(radius)

## Answer this Question

## Related Questions

- physics - A wheel rotates without friction about a stationary horizontal axis at...
- Physics... rotation - A constant force of 40 N is applied tangentially to the ...
- physics - A constant force of 20N is applied tangentially to a string wound on ...
- Physics - A bullet with a mass m = 4:83 g and initial speed of 330 m/s passes ...
- physics - THe steering wheel of a car has a diameter of 60cm and turns a shaft ...
- Physics - The combination of an applied force produces a constant total torque ...
- physics - A car weighing 1.07 x 10^4 N is at rest on a 32.5° incline. Each wheel...
- Physics - A 6 kg grinding wheel of radius 0.2 m rotates at a constant rotational...
- Physics - The combination of an applied force and a frictional force produces a ...
- Physics - A large grinding wheel in the shape of a solid cylinder of radius 0....

More Related Questions