A force F is exerted by a broom handle on the head of the broom, which is of mass m. The handle is at angle theda to the horizontal. (where it's tilted towards the left at about 30 degrees to the horizonal). The work is:
a)fdsin theda
b)fdcos theda
This would be b) right? Although the angle is a bit different that normal.
If the broom moves a distance d, and the force is applied in the direction of the broom handle, then the answer is (b)
the radi of the weel and axle are 20 cm and 4cm respectively
Yes, you are correct. The work done by the force F would be given by option (b), which is fd cos θ.
In this case, since the force is exerted in the direction of the broom handle and the handle is at an angle θ to the horizontal, the angle between the force vector and the displacement vector is θ. Therefore, the correct formula for work is fd cos θ.
You are correct, the work done by the force F can be calculated using the equation W = Fd cosθ, where W is the work done, F is the force applied, d is the distance over which the force is applied, and θ is the angle between the force vector and the displacement vector.
In this case, the force F is exerted along the direction of the broom handle, and the distance over which the force is applied is d. The angle θ is the angle between the force vector and the displacement vector, which is also the angle between the broom handle and the horizontal direction.
Since the force is applied along the broom handle and the broom moves in the same direction, the angle θ is 0 degrees. Therefore, cosθ = cos0° = 1, and the work done is W = Fd cosθ = Fd.
So, the correct answer is b) Fdcosθ.