Posted by **Tony** on Monday, March 26, 2007 at 12:48pm.

how do you solve

7(3x+4)=8(2x+5)+13

expand the parenthesis...I will do the left side..

21x + 29=

Now, subtract sixteen x from both sides, and subtract 28 from both sides.

I will be happy to check your work.

7(3x+4)=8(2x+5)+13

21x + 29

is 7 times 4 28?

21x+ 28= 16x+40+13

21x+28= 16x+ 53

21x+28-28 = 16x+53-28

21x-16x= 16x-16x+25

5x= 25

do I divide now?

5x/5 =25/5

x=5

am I right?

you are right. Good work.

## Answer This Question

## Related Questions

- algerbra - 7(3x+4)=8(2x+5)+13 how would I start a equation like this would it be...
- math - can anyone help me with these 3 problems I am trying to check my ...
- MATH PLEASE CHECK IT!!2 - m-2/m-5*m+5/m-2=-1 If your problem is this: (m - 2)/(m...
- Pre Cal - 6-x=2x+9 If you are to solve the equation for x, first try to get the ...
- math--pre alg - not sure i did right 3(f+2)+9=13+5f 3f+6+9 = 13+5f +9 3F+15 = 12...
- math - 2x+4(1-x)=11+5x 2x+4-4x=11+5x 6x+4=11+5x 6x=7+5x x=7 i think this is it x...
- Algebra - 2x + 1/2 = x/2 + 1/3 Subtract the x/2 from both sides to get 2x + 1/2...
- algebra - I need a step by step explanation on how to add these two equations 2x...
- Variable - SOLVING EQUATIONS WITH THE VARIABLE ON BOTH SIDES Solve the equation...
- Algebra - Solve S=a/(1-r) for r S = a/(1-r) Multiply both sides by 1-r S*(1-r...

More Related Questions