Thursday

July 24, 2014

July 24, 2014

Posted by **Jim** on Monday, March 26, 2007 at 12:53am.

In the drawing the radius is 1.2m and F is counterclockwise.

Net external torque=moment of Inertia X Angular acceleration

Moment of Inertia = sum of mass X r^2

= (88kg X 4)(1.2m^2)

=506.88

I transpose the above formula making angular acceleration the subject of the equation.

Angular acceleration= sum of external torque / Moment of inertia

angular acceleration= 63.6 / 506.88

=0.12547

This answer is incorrect please tell me where I went wrong.

The moment of inertia depends upon where the glass panes are placed, which your question does not explain. it is unfortunate that this web site cannot handle figures. In any case, the moment of inertia is not just the sum of masses of the panes multipied by some R^2. You have to use the parallel axis theorem. See

http://hyperphysics.phy-astr.gsu.edu/hbase/parax.html

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