Posted by **COFFEE** on Sunday, March 25, 2007 at 10:28pm.

The rigid body shown in Figure 10-66 (it is a triangle with the upper mass = to M and the bottom two corners/masses equal to 2M. The bottom side length equals .70 cm with point P in the middle of the side and the other two sides equal .55 cm)

consists of three particles connected by massless rods. It is to be rotated about an axis perpendicular to its plane through point P. If M = 0.40 kg, a = 35 cm, and b = 55 cm, how much work is required to take the body from rest to an angular speed of 5.0 rad/s?

*My work so far*

I believe I need to use:

W = (1/2)(I)(ang speed)^2

I am not sure how to find I though. Would I use I = I1 + I2 + I3 and calculate I for each of the 3 masses?

- Physics - KE/Inertia -
**Anonymous**, Thursday, March 20, 2008 at 6:20pm
1.51

## Answer This Question

## Related Questions

- Physics - KE/Inertia - The rigid body shown in Figure 10-66 (it is a triangle ...
- Physics - KE/inertia - The rigid body shown in Figure 10-66 (it is a triangle ...
- Physics - I can't figure this question out. If there are three weights attached ...
- physics - The center of mass and the moment of inertia of a 2D rigid body A 2D ...
- math - An art class is making a mural for their school which has a ...
- physics - Three equal positive point charges q are at the corners of an ...
- Physic II - In the figure Q=4.6 nC and all other quantities are exact. What is ...
- College physics - Center of mass - College Physics- Center of Mass? The objects ...
- Physics - Three masses that are 10 kg each are located at the corners of an ...
- Physics - Three weights are attached to the corners of an equilateral triangle (...

More Related Questions