Friday

March 6, 2015

March 6, 2015

Posted by **jas20** on Sunday, March 25, 2007 at 7:09pm.

Problem #1

Geometry. The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm, what are the dimensions (the length and the width) of the rectangle?

Problem#2

Science and medicine. The equation

h=-16t^2+112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112 ft/s, where t is the time after the arrow leaves the ground. Find the time it takes for the arrow to

reach a height of 180 ft.

first:

l-1=w

diagonal^2=length^2 + width^2

16=l^2 + (l+1)^2

solve for l

On the second, put 180 onto the equation , getting

16t^2 +112t - 180=0

or use the quadratic equation

I would divide by four to simplify it.

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