# algebra1

posted by
**Malik** on
.

Find to consecutive integers that the sum of 3 times the first integer and 6 times the second integer is 24. Define the variabls you use. If somebody can show me how to work this out, I will be very greatful for the help?

consecutive integers, n, n+1

3n + 6(n+1)=24 You need to put some thinking into these, it is not of much value to you if I do the work

I am not asking you to do the work .Just to show me the walk-through of how to get the answer. That's is all. I still appreciate the help that you have given me.