Wednesday
April 23, 2014

Homework Help: Chemistry

Posted by jim on Friday, March 23, 2007 at 8:58am.

when pure sodium hydroxide is dissolved in water , heat is evolved in a laboratory experiment measure a molar heat of solution of sodium hydroxide the following procedure was followed. to a calorimeter containing 300g of water at 20.0 C and 10.65g of NaOH also at 20.0 C was added. the temperature change which was monitered by digital probe with neglible heat capacity stopped when it reached a temperature of 28.50C if the specific heat of the mixture is 4.184Jg-1c-1 and the small heat capacity of the calorimeter is ignored what is Delta H for the solution of one moleof NaOH? the molar mass of NaOH is 40.09.

Compute the heat generated, Q, using the temperature rise and the mass M and heat capacity C of H2O.
Q = M C (delta T)
delta t is the 8.50 C change in temperature.
Divide Q by the number of moles of NaOH to get the deltaH per mole.

heat of solution is
massH2O*specificheatwater*deltaTH2O =
300g*4.184*(28.50-20.0) = ??joules.

??joules is the heat for 10.65g NaOH.
Convert to ?? joules/40.09 mol.
This is the heat of solution/mol NaOH.
Post your work if you get stuck.

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