posted by Charlene on .
picture in your mind a block that slides without friction down a ramp that is inclined at an angle (q) above the horizontal. Initially the block is at rest a distance (s) in meters (measured along the plane) from the bottom. Calculate the time (in seconds) required for the block to slide to the bottom.
can some1 show me the formula to find the time? for some reason, i can't find it in my textbook.
With no friction, the weight component down the ramp is Mg sin A, where g is the angle. That equals M a, so the acceleration is a = g sin A
The time T required is given by
(1/2)a T^2 = (1/2)g sin A
Solve for T