Posted by **Charlene** on Friday, March 23, 2007 at 3:00am.

picture in your mind a block that slides without friction down a ramp that is inclined at an angle (q) above the horizontal. Initially the block is at rest a distance (s) in meters (measured along the plane) from the bottom. Calculate the time (in seconds) required for the block to slide to the bottom.

can some1 show me the formula to find the time? for some reason, i can't find it in my textbook.

With no friction, the weight component down the ramp is Mg sin A, where g is the angle. That equals M a, so the acceleration is a = g sin A

The time T required is given by

(1/2)a T^2 = (1/2)g sin A

Solve for T

## Answer This Question

## Related Questions

- RE: phhysics - Posted by Charlene on Friday, March 23, 2007 at 3:00am. picture ...
- Physics - An 8.70 kg block slides with an initial speed of 1.56 m/s **down** a ...
- Physics - An 8.74-kg block slides with an initial speed of 1.52 m/s down a ramp ...
- College Physics - An 8.67-kg block slides with an initial speed of 1.50 m/s down...
- physics 221 - Question Part Points Submissions Used An 8.61-kg block slides with...
- physics - An 8.65-kg block slides with an initial speed of 1.52 m/s up a ramp ...
- Physics - A block of mass 2.00kg starts at rest at the top of a ramp that is ...
- physics - A 20 kg block slides with an initial speed of 11 m/s up a ramp ...
- physics - A 2.7 kg block, starting from rest, slides down a ramp with friction. ...
- Physics - Mechanics and Ocsillatory Motion - An 8.70 kg block slides with an ...

More Related Questions