Monday

July 28, 2014

July 28, 2014

Posted by **Charlene** on Friday, March 23, 2007 at 3:00am.

can some1 show me the formula to find the time? for some reason, i can't find it in my textbook.

With no friction, the weight component down the ramp is Mg sin A, where g is the angle. That equals M a, so the acceleration is a = g sin A

The time T required is given by

(1/2)a T^2 = (1/2)g sin A

Solve for T

**Related Questions**

Physics - An 8.70 kg block slides with an initial speed of 1.56 m/s **down** a ...

Physics - An 8.74-kg block slides with an initial speed of 1.52 m/s down a ramp ...

College Physics - An 8.67-kg block slides with an initial speed of 1.50 m/s down...

RE: phhysics - Posted by Charlene on Friday, March 23, 2007 at 3:00am. picture ...

physics 221 - Question Part Points Submissions Used An 8.61-kg block slides with...

physics - An 8.65-kg block slides with an initial speed of 1.52 m/s up a ramp ...

physics - A 20 kg block slides with an initial speed of 11 m/s up a ramp ...

Physics - Mechanics and Ocsillatory Motion - An 8.70 kg block slides with an ...

physics - The 2 kg block in Figure 7-25 slides down a frictionless curved ramp, ...

Physics - a block , mass .10 kg, slides from rest without friction down an ...