Rose's garden is in the shape of a trapezoid. If the height of the trapezoid is 16m, one base is 20m and the area is 224m2, what is the length of the other base?

The area of a trapezoid is:
A= (1/2) h (b1 + b2)
...where h = height and b1, b2 are the bases.

Substitute what you know to solve for the unknown.

224 = (1/2)(16)(20 + x)

Hopefully, you can solve for x, which will be the other base.

224= 16(20+b2)

2x224= 320+b2/2x2
Since 320+b2 over 2 has to multiply by 2 to get rid of the denominator, 224(area), has to also multiply by 2.
448=320+b2/2
320 divided by 2 is 160
448 divided by 2 is 224 again.
224=160
b2=160
Second base equals 160

how-

Let's solve for x:

224 = (1/2)(16)(20 + x)

To get rid of the fraction, we can multiply both sides of the equation by 2:

448 = 16(20 + x)

Next, distribute the 16 on the right side:

448 = 320 + 16x

Now, let's isolate the variable x by subtracting 320 from both sides:

448 - 320 = 16x

128 = 16x

To solve for x, we divide both sides by 16:

128/16 = x

x = 8

Therefore, the length of the other base is 8m.

To solve for the length of the other base, we can start by rearranging the formula for the area of a trapezoid:

A = (1/2)h(b1 + b2)

Given that the height (h) is 16m, one base (b1) is 20m, and the area (A) is 224m^2, we can substitute these values into the formula:

224 = (1/2)(16)(20 + b2)

Simplifying the equation gives us:

224 = 8(20 + b2)

224 = 160 + 8b2

Subtracting 160 from both sides:

64 = 8b2

Dividing both sides by 8:

8 = b2

Therefore, the length of the other base (b2) is 8m.