Given E° (Al3+|Al) = -1.66V and E° (Ag+|Ag) = .80V, calculate the overall cell potential when the two half-cells are connected.
My answer:
E°cell = E°(cathode) - E°(anode)
E°cell = .80 + 1.66 = 2.46
Is this correct?
That's right.
To calculate the overall cell potential when two half-cells are connected, you use the equation E°cell = E°(cathode) - E°(anode), where E°(cathode) represents the standard reduction potential of the cathode and E°(anode) represents the standard reduction potential of the anode.
In this case, E°(Ag+|Ag) is the standard reduction potential of the cathode, which is 0.80V. And E°(Al3+|Al) is the standard reduction potential of the anode, which is -1.66V.
Substituting these values into the equation, you get E°cell = 0.80V - (-1.66V), which simplifies to E°cell = 0.80V + 1.66V = 2.46V.
So, your answer of E°cell = 2.46V is correct.