Homework Help: chem

Posted by chris on Thursday, March 22, 2007 at 11:09pm.

hey guys I posted this awhile ago im not sure if anyone has read it or whatever but here it is again find the PH of a .00580 M solution of the strong base KOH.

is it -log(.00580)= 2.24

pOH = -log[OH-]
pH + pOH = 14.00

Therefore,
pOH = -log(.00580)
pH + 2.24 = 14
pH = 11.76

Remember, a pH above 7 is a base, and below is an acid.

Hope this helps.

right. Your 2.24 is ok. But you must remember that is pOH.
Then pH + pOH = pKw = 14.

No one has answered this question yet.

Answer this Question

Related Questions

english - hey people!! im new here and i just got an essay to do on english ...
chem - Hey you guys how do you find the moles of .75g of He
english (debate) - hey im in the negative side.the topic is no homeworks on ...
math. - hey guys i was just wondering if someone could help me with my 4 ...
Algebra HW - Find the vertex of the function y = –x2 + 2x + 8. it shows me ...
English - Hey guys, I was just wondering if you could help me find or explain ...
Math. - Hey thanks guys, im stuck XD 27.) if B + (-3) = -5 ; what is the value ...
science - hey guys, i need help again. wut iz density?
misc - im sorry i know i have posted this before but i forgot to go back on this...
Pencils - Hey guys, I know this is a homework site, but I cant seem to find this...

For Further Reading

First Name:
School Subject:
Answer: