posted by Jim .
I have no idea of how to solve this problem. Please help.
lunch tray is being held in one hand, as the drawing illustrates. The mass of the tray itself is 0.200 kg, and its center of gravity is located at its geometrical center. On the tray is a 1.00 kg plate of food and a 0.250 kg cup of coffee. Obtain the force T exerted by the thumb and the force F exerted by the four fingers. Both forces act perpendicular to the tray, which is being held parallel to the ground.
T = N (downward)(0.0500m)
F = N (upward) (0.100m)
The answer depends upon where the thumb, fingers, cup and plate are placed. A figure is needed. You solve it by setting net moments and forces equal to zero.