Posted by **Kyle** on Thursday, March 22, 2007 at 7:22pm.

Please help - I don't know where to begin. My problem is this: Find the numbers "Y" and "Z" if (1 and 3/5 times "Y") + (3/5 times "Z") = 5 AND (1 and 3/5 times "Z") + (3/5 times "Y") = 6. Thank You!

change 1 and 3/5 to another fraction:

8/5

so the equation is (8/5)Z+ (3/5)Z=5

now you can add 8/5 and 3/5 together because they both share Z.

so it would be 11/5Z=5. Multiply both sides by 5 to get 11Z=5 and divide 5 to both sides to get Z.

the second equation:

8/5(Z)+(3/5)Y=6

since you already know Z, plug it in, and find Y

Thank you!