find the PH of a .00580 M solution of the strong base KOH.
is it -log(.00580)=2.24
To find the pH of a solution of a strong base such as KOH, we need to calculate the pOH first and then convert it to pH.
The pOH can be calculated using the equation:
pOH = -log(OH-) concentration
In this case, the concentration of OH- ions is given as 0.00580 M. So, we can substitute this value into the equation:
pOH = -log(0.00580)
Now, to find the pH, we need to use the relationship between pH and pOH:
pH + pOH = 14
Since we have the pOH, we can rearrange the equation to solve for pH:
pH = 14 - pOH
Now, let's plug in the value of pOH that we calculated earlier:
pH = 14 - (-log(0.00580))
To simplify the expression, we can move the negative sign inside the logarithm:
pH = 14 + log(0.00580)
Using a calculator to evaluate log(0.00580), we get approximately -2.24.
Therefore, the pH of a 0.00580 M solution of the strong base KOH is approximately 14 + (-2.24) = 11.76.