how do u calculate the percentage of water of cystallisation in FeSO4.7H2O
percent water= 7*molmassH20/molmassFeSO4.7H2O * 100
now to get the mole mass of FeSO4.7H2O * 100, it is the sum of the atomic mass of one Fe, one S, four O, 14H, and 7 O.
To calculate the percentage of water of crystallization in FeSO4.7H2O, you need to follow these steps:
1. Determine the molar mass of H2O: The molar mass of water (H2O) is calculated by adding the atomic masses of two hydrogen atoms (2 x atomic mass of H) and one oxygen atom (1 x atomic mass of O). The atomic mass of hydrogen (H) is 1.008 grams/mole, and the atomic mass of oxygen (O) is 16.00 grams/mole. So, the molar mass of H2O is 18.02 grams/mole.
2. Determine the molar mass of FeSO4.7H2O: To calculate the molar mass of FeSO4.7H2O, you need to consider the atomic masses of iron (Fe), sulfur (S), oxygen (O), and hydrogen (H), as well as the seven water molecules (H2O) present in the compound. Add up the atomic masses of each element to obtain the molar mass. The atomic masses of Fe, S, O, and H can be found on the periodic table.
3. Calculate the percentage of water of crystallization: Divide the molar mass of H2O by the molar mass of FeSO4.7H2O, and then multiply by 100 to get the percentage. This calculation gives you the ratio of the molar mass of water to the molar mass of the entire compound.
For example, let's say the molar mass of H2O is 18.02 grams/mole and the molar mass of FeSO4.7H2O is 278.02 grams/mole. Using the formula mentioned above:
Percent water = (7 * molar mass H2O / molar mass FeSO4.7H2O) * 100
= (7 * 18.02 / 278.02) * 100
= 45.04%
Therefore, the percentage of water of crystallization in FeSO4.7H2O is approximately 45.04%.