Sunday

April 20, 2014

April 20, 2014

Posted by **kimberley** on Wednesday, March 21, 2007 at 4:36pm.

When the spring stops, there is no kinetic energy and the potential energy lost (M g X) equals the added potential energy of the spring, (1/2) k X^2.

(a) Since you know M = 3.00 kg, g = 9.8 m/s^2 and H = 0.100 mm, you can solve for the spring constant k.

(b) Use the enery conservation law and the fact that the energy stored in the spring is 1/4 as large when X = 5 cm, as it is at X = 10 cm.

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