Sunday

March 29, 2015

March 29, 2015

Posted by **kimberley** on Wednesday, March 21, 2007 at 4:36pm.

When the spring stops, there is no kinetic energy and the potential energy lost (M g X) equals the added potential energy of the spring, (1/2) k X^2.

(a) Since you know M = 3.00 kg, g = 9.8 m/s^2 and H = 0.100 mm, you can solve for the spring constant k.

(b) Use the enery conservation law and the fact that the energy stored in the spring is 1/4 as large when X = 5 cm, as it is at X = 10 cm.

- Physics Problem -
**hgfh**, Monday, November 17, 2014 at 7:34pmhfghgf

**Answer this Question**

**Related Questions**

Physics - 3 kg object is fastened to a light spring with the intervening cord ...

Physics - A block of mass m1 = 22.0 kg is connected to a block of mass m2 = 40.0...

Physics - I was given this problem, and are having problems. I am taking AP ...

Physics - Blocks of mass m1 and m2 are connected by a massless string that ...

physics - One end of a light spring with force constant 300 N/m is attached to a...

Physics - A block of mass m = 3.65 kg is attached to a spring (k = 27.5 N/m) by ...

physics - A block of mass m = 2.67 kg is attached to a spring (k = 32.3 N/m) by ...

physics - A block of mass m = 5 kg is attached to a spring (k = 35 N/m) by a ...

physics - A block of mass m = 5 kg is attached to a spring (k = 28 N/m) by a ...

physics/ torques - A block of mass m = 5 kg is attached to a spring (k = 35 N/m...