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September 18, 2014

September 18, 2014

Posted by **steph** on Wednesday, March 21, 2007 at 4:33pm.

I tried to do this problem and i still cant figure it out..please help..it would be great is the work was shown ..thanks in advance

"it would be great if the work was shown .."

It sure would.

The period of a pendulm is

P = 2 pi sqrt (L/g)

L is the length of the pendulum and g is the acceleration of gravity.

On the moon, g is 1.63/9.81 = 0.166 as high as it is on earth. Ask yourself How long it would take to register 24 hours on the moon. Pendulum clocks work by counting the number of swings.

And please show your work if you need further help.

- physics -
**Fig**, Wednesday, October 20, 2010 at 5:03pm9g of the moon is .166*g on earth.

T pendulum is 2*pi(L/g)^.5

Because g of the moon is .166*g on earth, T moon is 2*pi(L/.166g)^.5

This goes to T moon= (1/.166)^.5*T on earth.

T on earth for 24 hours is 24 hours. Convert that to seconds and multiply by (1/.166)^.5

Your answer will be the seconds that pass on the moon. From there you can find hours, minutes, and second elapsed.

- physics -
**Fig**, Wednesday, October 20, 2010 at 5:04pmThere should be no 9 at the beginning of my previous post. Sorry.

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