Posted by **Nicole** on Tuesday, March 20, 2007 at 10:44pm.

Suppose you have a meter stick with two masses attached. The mass m1 is 0.60 kg and it is located at x1 = 30 cm from the left (zero) end of the meter stick. The pivot point is located at x = 45 cm. The mass of the meter stick (mms = 0.40 kg) is located at its geometric center, xms = 50 cm. The mass m2 is 0.25 kg and it is located at x2 = 80 cm from the left end of the meter stick. Calculate the net torque (in N⋅m with the proper sign) due to these three weights. Use g = 9.8 m/s2.

Mass m1 exerts a force m1*g at a distance of 15 cm (0.15 m) left of pivot point. That creates a counterclockwise torque of 0.6*9.8*0.15 N-m. The mass of the meter stick exerts a gravitational force ms*g through a piint 5 cm to the right of the pivot, creating a clockwise torque. Mass m2 exerts a force m2*g that is applied 35 cm to the right of the pivot.

All you have to do is compute the three torques and add them. Treat the counterclockwise torque as negative.

If you need more assistance with this one, please show your work.

## Answer this Question

## Related Questions

- Physics-torques - Suppose that a meter stick is balanced at its center. A 0.27-...
- College Physics - A uniform meter stick of mass M has an empty paint can of mass...
- physics 2, help please - Two masses (mA= 2 kg, mB= 4 kg) are attached to a (...
- physics - A 65 g meter stick has two masses, each 250 g placed upon it. The ...
- physics - if the fulcrum of a .15 kg meter stick was placed at 25 cm and a 300 ...
- physics - if the fulcrum of a .15 kg meter stick was placed at 25 cm and a 300 g...
- Physics - A meter stick weighs 200 grams and is supported at the center. Three ...
- physics - The meter stick in the drawing can rotate about an axis located at the...
- physics - A meter stick is held vertically with one end on the floor and is then...
- physics - A .100 kg meter stick is supported at its 40.0 cm mark by a string ...

More Related Questions