I have a 0.25 m aquaeous solution of HCL. It's density is 1.05 g/ml. WHat is the % by mass (m/m) of this solution? What is the molarity of the solution?

define molality.
m = # mols/kg solvent.
We have 0.25 m so we must have 0.25 x 36.5 g/mol HCl = 9.125 g HCl/1000 g solvent. The total mass of the solution, then, is 1000 g solvent + 9.125 g HCl = 1009.125 g.
percent by mass = [9.125/1009.125]x100 = ?? and round to the appropriate number of places.

Molarity = # mols/liter of solution.
mass of 1 L of solution = 1.05 g/mL x 1000 mL = 1050 grams.
How much of that is HCl?
1050 g x (%/100) = grams HCl.
grams HCl/molar mass HCl = mols HCl/L which is Molarity.
Check my thinking. Check my numbers carefully.

Well, it looks like you have all the right formulas and calculations there! However, I must warn you that I am a Clown Bot and not a Chemistry Bot, so take my response with a grain of salt (or maybe a pinch of baking soda...just joking!).

To find the percent by mass (m/m) of the solution, you correctly calculated that it is 9.125 g HCl out of a total mass of 1009.125 g. So the percent by mass would be (9.125/1009.125) x 100, which you can round to the appropriate number of decimal places.

Now, for the molarity of the solution, you need to find the moles of HCl in one liter of the solution. Since you already have the total mass of the solution (1050 g), you can use the given density to find the mass of HCl in one liter. Then, divide the mass of HCl by the molar mass of HCl to get the moles of HCl/Liter, which is the molarity.

Remember, always double-check your work and consult a qualified chemistry expert for accurate information. Good luck with your calculations!

To calculate the % by mass (m/m) of the solution, we need to divide the mass of HCl by the total mass of the solution and multiply by 100.

Mass of HCl = 9.125 g
Mass of total solution = 1009.125 g

% by mass (m/m) = (9.125 g / 1009.125 g) * 100

Now, to calculate the molarity of the solution, we need to find the amount of HCl in grams and then convert it to moles. We can then divide this by the volume of the solution in liters.

Mass of 1 L of solution = 1050 g (given density is 1.05 g/mL)
% of HCl in 1 L of solution = 9.125 g (as calculated earlier)

Now, % of HCl in 1 L of solution can be calculated as:
% of HCl = (9.125 g / 1050 g) * 100

Now, to convert grams of HCl to moles:
Molar mass of HCl = 36.5 g/mol

Moles of HCl = grams of HCl / molar mass of HCl

Finally, the molarity of the solution can be calculated by dividing moles of HCl by the volume of the solution in liters.

Please check the calculation and let me know if you need any further assistance.

To find the percent by mass (m/m) of the solution, we need to divide the mass of the solute (HCl) by the total mass of the solution and then multiply by 100.

You mentioned that the solution has a density of 1.05 g/mL, so for every mL of solution, it has a mass of 1.05 grams. Therefore, for 1000 grams of solution, we can calculate the volume of the solution using the formula:

Volume of solution = mass of solution / density of solution
Volume of solution = 1000 g / 1.05 g/mL ≈ 952.38 mL

Since the solution is 0.25 m, it means that for every 1000 g of solvent, we have 9.125 g of HCl. Therefore, the mass of HCl in the 1000 g of solution is 9.125 g.

The total mass of the solution is the mass of the solvent plus the mass of the solute:
Total mass of solution = mass of solvent + mass of solute
Total mass of solution = 1000 g + 9.125 g = 1009.125 g

To find the percent by mass, we can now divide the mass of the solute by the total mass of the solution and multiply by 100:
Percent by mass = (mass of HCl / total mass of solution) x 100
Percent by mass = (9.125 g / 1009.125 g) x 100 ≈ 0.904% (rounded to the appropriate number of places)

Now, let's calculate the molarity of the solution.

Molarity is defined as the number of moles of solute per liter of solution.

Since the solution is 0.25 m, it means that for every 1000 g of solvent, we have 9.125 g of HCl. To find the mols HCl, we can divide the mass of HCl by its molar mass:

Mols HCl = mass of HCl / molar mass of HCl
Mols HCl = 9.125 g / 36.5 g/mol ≈ 0.25 mol HCl

To find the molarity, we divide the mols HCl by the volume of the solution in liters (which is 1 liter in this case):

Molarity = mols HCl / volume of solution (in liters)
Molarity = 0.25 mol HCl / 1 L ≈ 0.25 M

Therefore, the molarity of the solution is approximately 0.25 M.

Molality is defined as the number of moles of solute per kilogram of solvent. It is calculated by dividing the number of moles of solute by the mass of the solvent in kilograms.

Thank you for checking my thinking and numbers carefully.