Posted by **winterWX** on Monday, March 19, 2007 at 11:54pm.

A small block of mass m = 4.0 kg can slide along the frictionless loop-the-loop. The block is released from rest at point P, at height h = 23R above the bottom of the loop (R is the radius of the loop). Express your answers in the form ngR, where n is the number you will calculate.

a) What is the potential energy when the block is at point P? (Assume the gravitational potential energy of the block Earth system is taken to be zero at the bottom of the loop).

b) What is the potential energy when the block is at point Q (halfway up the loop)?

c) What is the kinetic energy when the block is at the top of the loop?

We don't do homework for you here. Show us some effort and someone will critique your work or thought process.

## Answer This Question

## Related Questions

- physics - A small block of mass m can slide along the frictionless loop-the loop...
- physics - A small block of mass 42 kg slides along a frictionless loop-the-loop...
- Physics - In the figure below, a small block of mass m = 0.034 kg can slide ...
- Physics - A small block of mass m = 1.3 kg slides, without friction, along the ...
- physics - A small block of mass m = 1.1 kg slides, without friction, along the ...
- physics - A small block of mass m = 1.1 kg slides, without friction, along the ...
- Physics - A small block of mass m=1.9kg slides, without friction, along the loop...
- Physics - A small block of mass m=1.9kg slides, without friction, along the loop...
- Physics - A massless spring of constant k = 91.0 N/m is fixed on the left side ...
- physics - A massless spring of constant k =60.9 N/m is fixed on the left side of...

More Related Questions