Monday

July 28, 2014

July 28, 2014

Posted by **Joan** on Monday, March 19, 2007 at 9:19pm.

Which of the following series can be used to compute ln(.8)?

a) ln(x-1) expanded about x=0

b) lnx about x=0

c) ln x in powers of (x-1)

d) ln(x-1) in powers of (x-1)

e) none of the proceding

I am confused... please help!

I am not certain any of our volunteers have expandied series of log functions in the recent past, and would likely give you misleading info. Perhaps one of the non regular math profs will drop in and help you.

The Taylor Series says:

ln(x)== ln(a) + (x-a) / a - (x-a)2 / 2a2 + (x-a)3 / 3a3 - (x-a)4 / 4a4 + ...

where a is a value for which you know ln(a)

your x=.8, then I would choose a=1

and

ln(.8)=ln(1)+(-.2)/1+(-.2)^2/2+(-.2)^3/3...

=0+a series of negative terms.

I did this for 5 terms and got -.2233866

with the real value of ln(.8)=-.22314..

**Related Questions**

Calculus - Please.... I need your help! I posted this question yesterday and no ...

Algebra - I posted this earlier but it didn't get answered. So I'm posting it ...

Physics- Repost Please Help - Posted by Amanda E. on Saturday, February 19, 2011...

calculus - I posted this below, and no one answered. Please help with this very ...

calculus - I posted this below, and no one answered. Please help with this very ...

Algebra II repost- please check - I posted these a little while ago but this ...

Science - What is the average summer temperature in the desert biome? Select one...

English Essay Writing - I posted my English essay homework on March 17,2008 and ...

grade 10 math - im stuck in this question,i tried everything but i failed... can...

calorimetry - please, someone answer my question i posted already I answered ...