Thursday

August 21, 2014

August 21, 2014

Posted by **cheryl** on Monday, March 19, 2007 at 11:01am.

distance =rate*time

The distance is the same.

y = rate going

z = rate returning

Going: d = y*t = y*5 = 5y

return: d = z*t = z*4 = 4z

we know the return rate was 5 mi/hr faster; therefore, the return rate of z = y+5

set d = d

5y=4z

z=y+5

=========

Solve simultaneously

Post your work if you need further assistance.

many students find distance-rate-time problems really easy if they make a chart

..........│..D..│..R..│..T..│

----------------------------

1st trip..│.5x..│..x..│..5..│

----------------------------

2nd trip..│4(x+5)│x+5│..4..│

clearly the two trips are the same

so 5x=4(x+5).........etc, piece of cake

The chart really IS a good idea.

**Related Questions**

science and medicine - I am having some trouble working this out . Could you ...

algebra - These are very easy to set up with a "chart" ---------Distance-----...

math - Sam took traveled 8 hrs to his sisters house. The return trip took 7 hrs ...

algebra - A bicyclist rode into the country for 5hr. In returning her speed was ...

algebra - Science and medicine. A bicyclist rode into the country for 5 h. In ...

Help...More Math Help!!!...Please! - A kayaker paddled 2 hours with a 6 mph ...

math - it took cindy 2h to bike from abbott to benson at a constant speed. the ...

Math Vocabulary - What does distance/ time/ rate of speed mean? It's all one ...

math,help - Also, can someone set this problem up into equations so i can solve....

algebra - A consultant traveled 7 hours to attend a meeting. The return trip ...