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September 15, 2014

September 15, 2014

Posted by **M** on Sunday, March 18, 2007 at 10:52pm.

Write 1/(x^3 +1) as

1/[(x+1)(x^2-x+1)]

Then use integration by parts, letting

dv = dx/(x^2 -x +1)

u = 1/(x+1)

du = log (x+1)

v = (2/sqrt3)arctan[(2x-1)/sqrt3]

That should take you to the answer. I know what the answer is (from my table of integrals), but have not done all the steps.

Could you by any chance tell me what your table of integrals says. I can't find it on mine to check my answer

OK. The answer is

(1/3){(1/2)log[(x+1)^2/(x^2-x+1)] + sqrt3*arctan[(2x-1)/sqrt3]}

Quite a mess. My approach does seem to lead to that answer.

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