How many grams of hydrochloric acid are required to react completely with 4.30g of zinc?
How many molecules of gas will be produced?
1. Write the balanced chemical equation.
Zn + 2HCl ==> ZnCl2 + H2
2. Convert grams Zn to mols.
mols = grams/atomic mass Zn.
3. Using the balanced equation, convert mols Zn to mols HCl.
4. Now convert mols HCl to grams HCl.
grams HCl = mols HCl x molar mass HCl.
Post your work if you get stuck.
Zn=1 Zn=1
H=2 H=2
Cl=2 Cl=2
mols= 4.30/65.4
=.065749235
I don't know what to do next
mol of HCl=73?
1. Write the balanced chemical equation.
Zn + 2HCl ==> ZnCl2 + H2
2. Convert grams Zn to mols.
mols = grams/atomic mass Zn.
You have 4.30/65.4 = 0.0658 mols Zn which is correct.
3. Using the balanced equation, convert mols Zn to mols HCl.
Use the coefficients in the balanced equation to convert mols Zn to mols HCl.
mols HCl = 0.0658 mols Zn x (2 mols HCl/1 mol Zn) =?? mols HCl
4. Now convert mols HCl to grams HCl.
grams HCl = mols HCl x molar mass HCl.
??mols HCl from step 3 x molar mass HCl = xx
post your work if you have trouble.
4.74
what is the answer for questions a and b? or have we gotten there yet?
grams HCl is thre answer for a.
For part b, work through the same problem but this time you want to find mols of H2 gas. When you know mols, remember that 22.4 L is 1 mol of H2 and use that to determine the volume of H2.
a,3.98527
To find the answer to part a, we need to continue with step 4 and calculate the grams of HCl.
4. Now convert mols HCl to grams HCl.
grams HCl = mols HCl x molar mass HCl.
Since you mentioned that the number of mols of HCl is 4.74, we can now calculate the grams of HCl.
grams HCl = 4.74 mols HCl x molar mass HCl.
To calculate the molar mass of HCl, we need to add the atomic mass of hydrogen (H) and the atomic mass of chlorine (Cl).
Molar mass HCl = atomic mass H + atomic mass Cl
Molar mass HCl = (1.008 g/mol) + (35.453 g/mol)
Molar mass HCl = 36.461 g/mol
Now we can plug the values into the equation to find the grams of HCl.
grams HCl = 4.74 mols HCl x 36.461 g/mol
By calculating this, we get the answer for part a, which is the grams of HCl required to react completely with 4.30g of zinc.