Posted by **Steven** on Saturday, March 17, 2007 at 10:35pm.

The Taylor series about x=5 for a certain function f converges to f(x) for all x in the interval of convergence. The nth derivative of f at x=5 is given by f^(n) (5)= (-1)^n(n!)/((2^n)(n+2)), and f(5)=1/2.

Write third degree Taylor polynomial for f about x=5. Then find the radius of convergence of the Taylor series for f about x=5.

Please help me solve this problem step by step. Thanks a lot!

## Answer This Question

## Related Questions

- Calculus - Please.... I need your help! I posted this question yesterday and no ...
- Calculus - Can someone prove (informally) the following theory: If there is a ...
- Calculus - a) Find the Taylor series associated to f(x) = x^-2 at a = 1. Be sure...
- Taylor seires - f(x) =ln (1-x) a) Compute f'(x), f''(x), f'''(x). Spot the ...
- Calculus - What is the radius of convergence of the power series (((2n)!x^(n...
- Maths - Use the binomial series to find the Taylor series about 0 for the ...
- Calculus - If you have a geometric alternating series, and you prove that the ...
- Calculus - For what values of p>0 does the series Riemann Sum [n=1 to ...
- calculus - test the series for convergence or divergence. the sum from n=1 to ...
- calculus - test the series for convergence or divergence. the sum from n=1 to ...

More Related Questions