Posted by **Anonymous** on Saturday, March 17, 2007 at 7:04pm.

okay the question is as follows:

determine the coefficient of the middle term in the expanxion of

(2x-3)^ 10

n/2 = 10/2 = 5

10C5 (2x)^10-3 (-3)^5 =

252(128X^5)(243)

= 7838208x^5

is this correct? thanks in advance!?

## Answer This Question

## Related Questions

- Math 30 - The first 3 terms in one row in the Pascals triangle are 1, 10, and 45...
- math - The value of the term middle in the expansion (2x2 + 1)10 , x=0.5 is: (a...
- number pattern - if term 6=-243 and term 3=72 of a geometric sequence determine...
- Pre Calculus 12 urgent - andrew is working on a binomial problem (1/2x-y)^7. He ...
- Math Algebra - I’m working on factoring trinomials of the form ax2 + bx + c & ...
- math,help - how do i find the following: is there a formula for this? Problem #...
- Math - Find X 27^4x-2=243^3x+6 Please explain how to do it. Thanks 27^(4x-2)=243...
- algebra - Solve each equation by factoring. 7x²-243=0 I know I'm supposed to add...
- Binomial Theoram - Show that the coefficient of the middle term of(1+x)power2n ...
- math - Find the fifth term of a geometric sequence whose fourth term is 8/9 and ...

More Related Questions