How many hours of jogging at 5 1/2mi/h would be needed for a 200 pound person to lose 5 pounds and it takes 3500 cal for one pound 740 cal/h for jogging 5 1/2 mi/h
Please post your answer, and we'll be glad to critique it.
750x3500
740x3500=2590
No, not right.
If it takes 3500 burned calories to lost 1 lb, then it takes 5 * 3500 = 17,500 cal to lose 5 lb
Now let N be the number of hours needed to lose 5 lb.
N (h) * 740 (cal/h) = 17500 cal
N = 17500/740 = 23.6 h
To calculate the number of hours needed for a 200-pound person to lose 5 pounds through jogging at a speed of 5 1/2 mi/h, we need to consider the following information:
1. It takes 3500 calories to lose 1 pound of weight.
2. Jogging at a speed of 5 1/2 mi/h burns 740 calories per hour.
To find the total calories needed to lose 5 pounds, we multiply 5 pounds by 3500 calories/pound:
5 pounds * 3500 calories/pound = 17500 calories
This means that the person needs to burn 17500 calories through jogging.
Now, let's determine the number of hours needed to burn these calories.
Let N represent the number of hours needed.
N (hours) * 740 (calories/hour) = 17500 calories
To solve for N, we divide 17500 calories by 740 calories/hour:
N = 17500 calories / 740 calories/hour
N = 23.6 hours
Therefore, it would take approximately 23.6 hours of jogging at 5 1/2 mi/h for a 200-pound person to lose 5 pounds.