Thursday

March 5, 2015

March 5, 2015

Posted by **jasort20** on Friday, March 16, 2007 at 2:26am.

Problem #1

Write in simplest form

(48a^5b)/(12ab^2)

this is what i get:

4a^4b^-1

Problem #2

how do i start it:

subtract. Express your result in simplest form

(12)/(z) minus (10)/(z)

Your #1 is correct, and can also be written 4a^4/b.

#2 12/z - 10/z = (12-10)*(1/z) = 2/z

canyou explain to me how do you determine to make it a 1/z

Z is a common denominator, so you can just add or subtract the numerators.

12/z - 10/z = (!2-10)/z = 2/z

The same thing is accomplished by extracting 1/z.

12/z - 10/z = (!2-10)(1/z) = 2/z

I hope this helps a little more. Thanks for asking.

thank you yes it does i appreciated...

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