How do write a skeleton equation for this reaction?

When heated, baking soda (sodium hydrogen carbonate) decomposes to form the products sodium carbonate, carbon dioxide, and water.

Can someone please break it down so i can see how you got that ansewer? Thanks in advance

NaHCO3 ==> Na2CO3 + H2O + CO2

Some like to do this in two steps.
NaHCO3 ==> Na2CO3 + H2CO3
H2CO3 ==> H2O + CO2

To write a skeleton equation for this reaction, we need to first identify the reactants and products involved.

Reactants:
- Baking soda (sodium hydrogen carbonate) - NaHCO3

Products:
- Sodium carbonate - Na2CO3
- Water - H2O
- Carbon dioxide - CO2

Now, we need to balance the equation by making sure the number of atoms of each element is the same on both sides.

Step 1:
We start with the decomposition of baking soda reaction: NaHCO3 ==> Na2CO3 + H2CO3

Here, we have one sodium atom (Na) on the reactant side and two sodium atoms on the product side, so we need to double the sodium carbonate in the products: NaHCO3 ==> 2Na2CO3 + H2CO3

Next, we move to the decomposition of carbonic acid reaction: H2CO3 ==> H2O + CO2

Here, we have two hydrogen atoms (H) on the reactant side and only one hydrogen atom in the products, so we need to double the water in the products: H2CO3 ==> 2H2O + CO2

Now, combining both reactions and simplifying the coefficients, we get the final skeleton equation:

NaHCO3 ==> Na2CO3 + H2O + CO2