February 27, 2017

Homework Help: physics.

Posted by Jean on Thursday, March 15, 2007 at 5:38am.

A 20.0 kg cannon ball is fired from a cannnon with muzzle speed of 1000 m/s at an angle of 37.0 with the horizontal. A second ball is fired at an angle of 90.0. Use the conservation of energy principle to find
a] the maximum height reached by each ball and
b] the total mechanical energy at the maximum height for each ball. Let y=0 at the cannon

For the first cannon, find the vertical component of velocity. Because the horizontal velocity is constant, the portion of KE that converts to gpe is given by 1/2 m vvertical^2.

mgh= 1/2 m vvertical^2 Solve for h.

a) Let Voy be the INITIAL vertical velocity component of either cannonball.
The maximum height H reached is given by
g H = (1/2)Voy^2
For the cannonball fired at 37 degrees,
Voy = 1000 sin 37 = 601.8 m/s
for the one fired vertially,
Voy = 1000 m/s
Now complete the calculation of h for each case
b) You can save your self severalsteps by using the fact that the total mechanical energy remains equal to the initial kinetic energy:
Etotal = (1/2) M V^2

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