# trig

posted by
**natash**
.

how do you solve Fcos29(degree)-210.308-0.58Fsin29=0

Solving for F?

F(cos269-.58sin29)=210.308

F= 210.308/(cos269-.58sin29)

posted by
**natash**
.

how do you solve Fcos29(degree)-210.308-0.58Fsin29=0

Solving for F?

F(cos269-.58sin29)=210.308

F= 210.308/(cos269-.58sin29)