Posted by **drwls** on Tuesday, March 13, 2007 at 10:57pm.

The stored potential energy in the trampoline at maximum compression, (1/2) k X^2, equals the gravitational potential energy at maximum height, M g H. (Kinetic energy is zero in both cases)

X = 0.5 m

g = 9.8 m/s^2

H = 2.5 m

k = the spring constant.

Solve for k.

k = 2MgH/X^2

A 115 kg man is jumping on a trampoline. If the trampoline is compressed .5 meters and the maximum height is 2.5 meters above the trampoline, what is the spring constant?

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