Posted by **Joe** on Tuesday, March 13, 2007 at 10:36pm.

How do I do this problem?

1. A student did an alkalinity determination correctly, except that the sample titrated had a volume of 90.0 mL. Volume A was found to be 4.50 mL and Volume B was 7.00 mL.

a) Calculate the alkalinity value from these data and then calculate the correct value.

I got this far: A=(2A-B)

A=(2(4.50)-7.00)= 2 mL^-1

Now what do I do?

You say "except that the sample titrated had a volume of 90.0 mL." What should it have been? If you titrated two 90.0 mL samples and found one 4.50 mL to the end point and another 7.00 mL to the end point, just calculate the alkalinity normally. The two won't agree of course, they won't even come close, but that's just poor precision.

## Answer This Question

## Related Questions

- college chemistry - a student did an alkalinity determination correctly,except ...
- Chemistry - Can someone check my answers? Thanks. 1.) If you were involved in an...
- Chemistry check - Can someone check my answers? Thanks. 1.) If you were involved...
- Chemistry - If the 50.00mL sample from problem 3 above was titrated with EDTA,...
- Chemistry - A 25.00 ml sample of a standard solution containing 1 g of CaCO3/L ...
- Chemistry (3rd time I've posted this) - Can someone check my answers? I've ...
- Chemistry - A 25.00mL sample of a household cleaning solution was diluted to 250...
- chemistry - A student determined the chloride content of a commercial salt by ...
- Chemistry - Suppose a student diluted and titrated a bleach unknown exactly as ...
- chemistry - A sample of an ideal gas at 1.00 atm and a volume of 1.61 L was ...

More Related Questions