Friday

December 19, 2014

December 19, 2014

Posted by **david** on Tuesday, March 13, 2007 at 10:24pm.

f(x)=4/sqrt(x), c=1

i'm totally confused on how to do it. i know you find the derivative but how do i get the function. this is number five on my homework so if you help me on this, i will be able to do the rest.

A first degree polynomial is a straight line of the form y = mx + b.

They are asking you for the equation of a line tangent to 4/sqrt(x) = 4 x^-(1/2) at x = 1

The value of y=f(x) at that point is y = 4

The value of the slope is

dy/dx = -2x^(-3/2), and when x=1, that slope is -2.

The equation of the tangent line is

(y-4)/(x-1) = -2

Convert that to y = mx + b form.

y-4 = -2x + 2

y = -2x + 6

**Answer this Question**

**Related Questions**

calculus - Let f be a function that has derivatives of all orders for all real ...

Calculus - Hi~ Thank you for your help! I was trying to work on a problem about ...

calculus - how do i use a taylor series centered at some x value to approximate ...

physics - I'm making a graph of force vs stretch for springs. I have 7 data ...

calculus - First I would find the first derivative which is the slope and then ...

calculus-- need help desperately! - The Taylor series about x=5 for a certain ...

Calculus - Taylor #2 - Find the Taylor series for f(x) centered at the given ...

Calculus - Please.... I need your help! I posted this question yesterday and no ...

math (taylor polynomials) - Find the degree 3 Taylor polynomial T3(x) of the ...

Calc 2 taylor series - use the definition of a taylor series to find the Taylor ...