Please help! Complete equation by drawing structural formula(e) of the product(s).

CH2=CH-CH-OH + CH3-CH-CH2-C =O
CH3 CH3 -OH

You will have to imagine the bonds as I can't draw vertical or diagonal lines!

There are too many possibilities to imagine what you are trying to draw. We simply can't draw structures. You will need to draw them in line drawings. For example, the first one is an alcohol, probably. Tell to which carbon the substituents are attached.The second one might be an acid;i.e., RCOOH. IF that is so, then alcohols (ROH) and acids (RCOOH) combine to form an ester with the elimination of water.
RCOOH + R'OH ==> RCOOR' + H2O where R is any alkyl group and R' is another alkyl group (but they may be the same). I simply used R' to keep the alkyl groups separate in your mind. If that is what you have it is fairly straight forward.

To determine the product(s) with a complete structural formula, we need to identify the reactants and understand their functional groups.

The first reactant, CH2=CH-CH-OH, is an alcohol. The OH group suggests that it is capable of reacting as a nucleophile.

The second reactant, CH3-CH-CH2-C=O, appears to be an aldehyde. The C=O group indicates that it is a carbonyl compound.

Based on these functional groups, we can deduce that an ester will be formed through the reaction between an alcohol and an aldehyde.

The general reaction can be represented as:

Alcohol + Aldehyde → Ester + Water

Now, let's consider the specific reactants given in your question:

CH2=CH-CH-OH + CH3-CH-CH2-C=O

To draw the structural formula of the product(s), we need to create a bond between the oxygen of the alcohol and the carbon of the aldehyde. At the same time, a bond needs to be broken between the carbon of the aldehyde and the oxygen. This rearrangement leads to the formation of an ester.

One possible product in this case could be:

CH2=CH-CH-O-CO-CH2-CH3

In this structure, the ester linkage is formed between the oxygen of the alcohol and the carbon of the aldehyde. The hydrogen from the alcohol is also transferred to the oxygen, creating a water molecule as a byproduct.

It is important to note that there might be other possible products depending on the reaction conditions and reactant concentrations. To determine the specific product(s), additional information such as reaction temperature, catalysts, and stoichiometry would be needed.