posted by holly on .
how do i do this question?
a ladder length 13m rests against a vertical wall with its foot on a horizontal floor at a distance of 5m from the wall. when the top of the ladder slips down a distance of x, the foot of the ladder moves out x. find the distance of x.
a^2 + b^2 = c^2
a^2 + 5^2 = 13^2 ==> 169-25=144=a^2
therefore a = 12
(12-x)^2 +(5+x)^2 = 13^2
144 - 24x +x^2 + 25 + 10x +x^2 = 169
x = 7 or 0
Therefore the distance moved is 7m.
but shouldn't it be 0 or -7?
oh, sorry, i get it