Posted by **winterWX** on Monday, March 12, 2007 at 1:57am.

The flywheel of a steam engine runs with a constant angular speed of 250 rev/min. When steam is shut off, the friction of the bearings stops the wheel in 2.1 h.

At the instant the flywheel is turning at 75 rev/min, what is the tangential component of the linear acceleration of a flywheel particle that is 50 cm from the axis of rotation?

The flywheel will decelerate at a uniform rate, since the frictional torque and moment of inertia can be sonsidered constant. That rate is

alpha = -(250 rev/min)*(2 pi rad/rev)*(60 min/sec)/[(2.1 hr)*(3600 sec/hr)]

-12.5 rad/s^2

Multiply that "alpha" by the radius to get the tangential component of acceleration for a point on the rim of the wheel. It will not matter what the rpm is at the time. RPM will affect the centripetal acceleration, however.

I tried that and got -6233 mm/s^2 or -6.23 m/s^2 but that is the wrong answer. What am I doing wrong? Thanks.

## Answer this Question

## Related Questions

- physics - The flywheel of a steam engine runs with a constant angular velocity ...
- Physics - The flywheel of a steam engine runs with a constant angular speed of ...
- PHYSICS!!! - The flywheel of a steam engine runs with a constant angular ...
- physics - The flywheel of a steam engine runs with a constant angular speed of ...
- physics - The flywheel of a steam engine runs with a constant angular speed of ...
- college physics - The flywheel of a steam engine runs with a constant angular ...
- Physics - The flywheel of a steam engine runs with a constant angular speed of ...
- physics - The flywheel of a steam engine runs with a constant angular speed of ...
- physics - drwls? - The flywheel of a steam engine runs with a constant angular ...
- Physics - A flywheel with a diameter of 2.45 m is rotating at an angular speed ...

More Related Questions