a would like to get someone too help me with these math problem.

Two angles of a triangle are 40 degrees and 62 degrees; what is the third angle's measur?

The angles of a triangle always adds to 180o. You know two of the angles, solve for the third.

can you please explained to me clearly beucase I don't understand it
thank you

Angle 1 + angle 2 + angle 3 = 180
Angle 1 = given
angle 2 = given
There is only one unknown in the equation. Solve for angle 3.

If you still don't understand, please explain in detail what you are having trouble understanding.

I do not know how to get the answer for the third angle, if two angles are 40 degrees and third is 62 degrees ; how do I do I do it do I multiplyor how do I get the answer yousee i been out of school for so long that I don't know how to do these math problems, i I have others problems that i haven't donne because I don't understand but thak you for helping me . but please explain these work

angle 1 + angle 2 + angle 3 = 180
angle 1 = 40 from the problem.
angle 2 = 62 from the problem.
angle 3 is not known.

40 + 62 + angle 3 = 180
add 40 + 62 = 102.
102 + angle 3 = 180
angle 3 = 180 - 102 = 78 degrees.

The width of a rectangle is 3 meters less than the length.The perimeter is 14 meters .Find the width.

The second angle of a triangle is twice the first angle. the third angle is 20 degrees mor than the first angle. Find the first angle.

One angle of a triangle is 20 degrees. The second angle's measuremant is four times the third . What is the measure of the third angle?

The sum of two angles in a triangle total 62.5 degrees. What is the other angle's measure?

W = L - 3M

2L + 2W = 14

2L + 2(L-3M) = 14
2L + 2L - 6 = 14
4L - 6 = 14
4L = 14 + 6
4L = 20
L = 20 / 4
L = 5

sub the value of L back into the perimeter fomula to find W.

2L + 2W = 14
2(5) + 2W = 14
10 + 2W = 14
2W = 14 - 10
2W = 4
W = 4 / 2
W = 2
_______________________________________

A + 20 = C

1/2B = A

A+B+C = 180
A+B+(A+20) = 180
2A + B + 20 = 180
2A + B = 180 - 20
2A + B = 160

since we know the value of A sub into formula

2A + B = 160
2(1/2B) + B = 160
B + B = 160
2B = 160
B = 160 / 2
B = 80

A+B+C = 180
A+ 80 + C = 180
A+C = 180 - 80
A + C = 100

from above sub. the value of C into the equation.

A + C = 100
A + (A + 20) = 100
2A + 20 = 100
2A = 100 - 20
2A = 80
A = 80 / 2
A = 40

We found the value of A and B sub. it back into the formula to find C.\

A + B + C = 180
40 + 80 + C = 180
120 + C = 180
C = 180 - 120
C = 60
_______________________________________

A = 20

B = 4C

A + B + C = 180
20 + B + C = 180
B + C = 180 - 20
B + C = 160

from above sub. the value of B into the equation.

B + C = 160
4C + C = 160
5C = 160
C =160 / 5
C= 32 degrees
_______________________________________

180 degrees-62.5 degrees= 117.5 degrees

general review for the high school student.

Sure, here's a general review for a high school student:

1. When finding the third angle of a triangle given two angles, you can use the fact that the sum of the angles of a triangle is always 180 degrees. Set up an equation where you add the known angles together and subtract the sum from 180 to find the third angle.

2. When finding the width of a rectangle given that it is 3 meters less than the length and the perimeter is known, you can set up an equation using the perimeter formula. Since the perimeter is the sum of all the sides, you can write an equation where you substitute the given information and solve for the width.

3. When finding the measure of angles in a triangle when given relationships between the angles, you can set up equations based on the given information and use algebra to solve for the unknown angles. Make sure you use the fact that the angles of a triangle sum up to 180 degrees.

4. When finding the measure of an angle given the sum of two angles in a triangle, you can subtract the sum from 180 degrees to find the missing angle.

Remember, practice makes perfect! The more you do these types of problems, the more comfortable you will become with them. Good luck!