Tuesday

September 16, 2014

September 16, 2014

Posted by **winterWX** on Saturday, March 10, 2007 at 12:31am.

(a) What is the angular velocity at t = 2 s?

(b)What is the angular velocity at t = 4.0 s?

(c) What is the average angular acceleration for the time interval that begins at t = 2 s and ends at t = 4.0 s?

(d) What is the instantaneous angular acceleration at the beginning of this time interval?

(e)What is the instantaneous angular acceleration at the end of this time interval?

(a) differentiate the theta(t) equation you provided. This will yield the following:

d(theta)/dt = omega(t) = 4 - 2t + 3 t^2

Then plug in t = 2 fr your answer.

The Greek letter "omega" is usually used for angular velocity.

(b) Use the same omega(t) formula but use t=4.

(c) Subtract the omega(2) from omega (4) for the angular velocity change, and divinde by 2 s.

(d) The formula for instantaneous angular acceleration is

alpha (t) = d(omega)/dt = -2 + 6t. Insert t = 2 s

(e) Insert t=4 into the alpha(t) equation above

**Answer this Question**

**Related Questions**

Physics - The angular position of a point on the rim of a rotating wheel is ...

Physics - The angular position of a point on the rim of a rotating wheel is ...

Physics - The angular position of a point on the rim of a rotating wheel is ...

physics - The angular position of a point on the rim of a 45.8 cm rotating wheel...

physics - A flywheel with a diameter of 1 m is initially at rest. Its angular ...

physics - A flywheel with a diameter of 1 m is initially at rest. Its angular ...

physics - A flywheel with a diameter of 1 m is initially at rest. Its angular ...

physics - A flywheel with a diameter of 1 m is initially at rest. Its angular ...

physic - The angular position of a point on the rim of a 45.8 cm rotating wheel ...

Physics - A wheel of arduous 30 cm is rotating at a rate of 2.0 revolutions ...